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Rooted by: Find distance between x and y
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  • Code 
    def distance(a):
    y,y1 = 0,0
    for i in range(len(a)):
        if "y" in a[i]: y = i
        if "x" in a[i]: y1 = i
        
    x ,x1 = a[y].index("y"), a[y1].index("x")
    return abs(x -x1) + abs(y-y1)
     Preloaded Code
    Test Cases 
    array = [1,1,1,"y",1],[1,1,1,1,1],[1,1,"x",1,1],[1,1,1,1,1]
test.assert_equals(distance(array),3)

array = [1,1,1,1,"y"],[1,1,1,1,1],[1,1,"x",1,1],[1,1,1,1,1]
test.assert_equals(distance(array),4)

array = [1,1,1,1,"y",1,1],[1,1,1,1,"x",1,1],[1,1,1,1,1,1,1],[1,1,1,1,1,1,1],[1,1,1,1,1,1,1],[1,1,1,1,1,1,1]
test.assert_equals(distance(array),1)

array = [1,"y",1],[1,1,1],[1,1,"x"]
test.assert_equals(distance(array),3)
    View Run Output
  • Code
    • def distance(array):
    • for i in range(len(array)):
    • if "y" in array[i] : y = abs(array[i].index("y") - i)
    • if "x" in array[i] : x = abs(array[i].index("x") - i)
    • return (x+y)
    • def distance(a):
    • y,y1 = 0,0
    • for i in range(len(a)):
    • if "y" in a[i]: y = i
    • if "x" in a[i]: y1 = i
    • x ,x1 = a[y].index("y"), a[y1].index("x")
    • return abs(x -x1) + abs(y-y1)