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Rooted by: Front Prueba Reto JS
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  • Code 
    def feed_the_primates_v1(animals, food):
    food = set(food)
    banana = "🍌"
    if banana not in food:
        return 'No bananas!'
    return [banana for m in animals if m in {"🐒", "🦍"} and banana in food]


def feed_the_primates_v2(animals: list, food: list) -> any:
    return 'No bananas!' if "🍌" not in food else list(
        map(lambda a: f"🍌{a}", filter(lambda m: m if m in ["🐒", "🦍"] else None, animals)))
    Test Cases 
    import timeit
import time
import codewars_test as test
from solution import feed_the_primates_v1, feed_the_primates_v2


@test.describe("Example")
def test_group():
    @test.it("test case")
    def test_case():

        solution_1 = timeit.timeit(stmt='feed_the_primates_v1(["🐒", "🐊", "🐘",  "🦍", "🦁", "🦒", "🐒", "🐒"], ["🍌",  "🍒", "🥥", '
                        '"🥝", "🍕", "🍒", "🥥","🍕"])',
                   setup='',
                   timer=time.perf_counter,
                   number=1000,
                   globals=globals())

        solution_2 = timeit.timeit(stmt='feed_the_primates_v2(["🐒", "🐊", "🐘",  "🦍", "🦁", "🦒", "🐒", "🐒"], ["🍌",  "🍒", "🥥", '
                        '"🥝", "🍕", "🍒", "🥥","🍕"])',
                   setup='',
                   timer=time.perf_counter,
                   number=1000,
                   globals=globals())
        
        test.assert_equals(solution_1 < solution_2, True)
    View Run Output
  • Code
    • def feed_the_primates_v1(animals, food):
    • if "🍌" not in food:
    • food = set(food)
    • banana = "🍌"
    • if banana not in food:
    • return 'No bananas!'
    • return [f"🍌" for m in animals if m in ["🐒", "🦍"] and "🍌" in food]
    • return [banana for m in animals if m in {"🐒", "🦍"} and banana in food]
    • def feed_the_primates_v2(animals: list, food: list) -> any:
    • return 'No bananas!' if "🍌" not in food else list(
    • map(lambda a: f"🍌{a}", filter(lambda m: m if m in ["🐒", "🦍"] else None, animals)))