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Kumite (ko͞omiˌtā) is the practice of taking techniques learned from Kata and applying them through the act of freestyle sparring.

You can create a new kumite by providing some initial code and optionally some test cases. From there other warriors can spar with you, by enhancing, refactoring and translating your code. There is no limit to how many warriors you can spar with.

A great use for kumite is to begin an idea for a kata as one. You can collaborate with other code warriors until you have it right, then you can convert it to a kata.

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Arrays
Data Types
Logic
Basic Language Features
Fundamentals
Strings

Write a function that takes as a parameter a starting square as a string in formal chess notation and determines the valid squares that the bishop can move to in one move for an empty chess board (only bishop on the board). Must return an array of valid squares in ascending square order.

function moveBishop($startingSquare)
{
    $result = [];
    $letters = ["a" =>  1, "b" => 2, "c" => 3, "d" => 4, "e" => 5, "f" => 6, "g" => 7, "h" => 8];   
    $startSqaureInDigits = $letters[$startingSquare[0]] . $startingSquare[1];
    
    // bishop movement is always two ways at the same time as it moves diagonally at least one space.
    // loop over 8 by 8 chessboard
    //i loop is for letters
    //j loop is for numbers
    
    for($i = 1; $i <= 8; $i++){
        for($j=1; $j <= 8; $j++)
        {
            if ($startSqaureInDigits != $i.$j &&  abs($startSqaureInDigits[0] - $i) ==  abs($startSqaureInDigits[1] - $j) ) 
            {
                $result[] = array_search($i,$letters).$j;
            }
        }
    }
    return $result;
}

Given a string of open and closed parenthesis output "Balanced" if the parenthesis are balanced or "Unbalanced" otherwise.

A string is balanced if it consists entirely of pairs of opening/closing parenthesis (in that order), none of which mis-nest.

Example input:
(())())

Example output:
Unbalanced

Example input:
(()())

Example output:
Balanced

function balanced_parenthesis(s) {
    if(s == null) return null;
    
    var i = 0,
        startCnt = 0,
        n = s.length;
 
    for(i = 0; i < n; i++) {
        if(s[i] === "(") {
            startCnt += 1;
        } else if(s[i] === ")") {
            startCnt -= 1;
            if(startCnt < 0) {
                break;
            }
        }
    }
 
    if(startCnt !== 0) {
        return 'Unbalanced';
    } else {
        return 'Balanced';
    }
}

def foo(l):
r = copy(l)
return r

l = [1,2]
print(l)
n = foo(l)
print(n)
l.append(7)
print(n)
print(l)

def foo(l):
	r = l
	return r

l = [1,2]
print(l)
n = foo(l)
print(n)
l.append(7)
print(n)
print(l)

Generate prime numbers within a given minimum and maximum.
min and max values should be positive (greater than 0).

import java.util.*;

public class Primes {
  public static List<Integer> generatePrimes(int min, int max) {
    List<Integer> primes = new ArrayList<Integer>();
    boolean isPrime = false;
    
    if((min > max) || min < 0 || max <= 0) {
      return null;
    }           
            
    for(int i = min; i <= max; i++) {
      long endLimit = (long)Math.floor(Math.sqrt(i));
      isPrime = true;
      for(long j = 2; j <= endLimit; j++) {
        if (i % j == 0) {
          isPrime = false;
          break;
        }
      }
    
      if(isPrime) {
        primes.add(i);
      }
    }
    
    return primes;
  }
}

How can u execute preloaded code in a c# kata.

I keep getting an error that the global namespace allready contains a definition for the Class in the Code block.

using System;

public static class Kata
{
  public static void test()
  {
    Person p = new Person();
  }
}
Algorithms
Logic
Mathematics
Numbers
Data Types

John likes numbers and digits. He takes digits of numder and sums squares of them.
Write function calc with input natural number n and output sum of squares of digits.

calc(1) = 1 // 1*1
calc(2) = 4 // 2*2
calc(123) = 14 // 1*1 + 2*2 + 3*3
calc(512) = 30 // 5*5 + 1*1 + 2*2

Also write function cumulate with input natural number n and output sum of function calc result for numbers from 1 to n.

cumulate(1) = 1 // calc(1) = 1
cumulate(2) = 5 // calc(1) + calc(2) = 1 + 4
cumulate(3) = 14 // calc(1) + calc(2) + calc(3) = 1 + 4 + 9
cumulate(12) = 293 // calc(1) + calc(2) + .. calc(11) + calc(12) = 1 + 4 + ... 2 + 5

Using special algorithm John found that

cumulate(12345678) = 2390700939
cumulate(123456789) = 27425527905
def calc n
  n.to_s.chars
		.map{|x|x.to_i**2}
		.reduce(:+)
end

def cumulate n
  sum_sq = ->(a,m){(a/m)*(a/m-1)*(a/m*2-1)/6*m+(a%m+1)*(a/m)**2}
  sum_bi = lambda do |a,u,v|
    t = (a/u)*(a/u/v)*(a+1-(a/u)*u)
	  ht = (a/u/v)*(a/u%v)*(2*(a/u)-1-a/u%v)/2
	  hha = v*sum_sq.(a/u/v*v-1,v)
	  hhb = (a/u/v)*(a/u/v-1)*v*(v-1)/4
	  (hhb+hha+ht)*u+t
  end
  (0..Math.log(n,10).ceil)
    .reduce(0){|s,d|s+sum_sq.(n,10**d)+100*sum_sq.(n,10*10**d)-20*sum_bi.(n,10**d,10)}
end
metaseanFailed Tests

Fizz Buzzy

There is a FizzBuzzy Race comming up. There will be a cone dropped at every mile marker divisable by 3 and 5, start at the start line.

When divisable by 3 and 5 there will be two cones dropped.

The start line is the 0th point and needs cones also.

The command will be: 'fizzbuzzy' and take the miles as the sole parameter.

function fizzbuzzy(n) {
  //insert code here
}
Hashes
Data Structures

Using HashMap in Java.

/* HashMap Example */
 
import java.util.*;
import java.lang.*;
import java.io.*;
 
class HashMapDemo
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Map<Integer, Integer> map = new HashMap<Integer, Integer>();
		map.put(1, 1);
		map.put(2, 1);
		map.put(3, 1);
		map.put(4, 1);
		map.put(5, 1);
		map.put(6, 1);
 
		for(Map.Entry<Integer, Integer> entry : map.entrySet()) {
			int key = entry.getKey();
			int value = entry.getValue();
			System.out.println(key + " " + value);
		}
	}
}

It should return result of lisp-like arithmetic expressions:

run("(+ 3 (* 2 4) 1)")  # 12
def run(code):
    
    def func(operator):
        from functools import reduce
        
        add    = lambda a, b: float(a) + float(b)
        mul    = lambda a, b: float(a) * float(b)
        div    = lambda a, b: float(a) / float(b)
        deduct = lambda a, b: float(a) - float(b)
        
        d = {
            '+': lambda arr: reduce(add,    arr),
            '*': lambda arr: reduce(mul,    arr),
            '/': lambda arr: reduce(div,    arr),
            '-': lambda arr: reduce(deduct, arr)
        }
        
        return d[operator]
    
    def lex(token):
        if token in ('+', '-', '/', '*', '%'):
            return "operator"
        elif token == '(':
            return "lbracket"
        elif token == ')':
            return "rbracket"
        elif token[0].isalpha():
            return "name"
        elif token[0] == token[-1] and token[0] in ('"', "'"):
            return "string"
        else:
            try:
                float(token)
                return "number"
            except:
                raise ValueError
            
    def getArgs(words):
        args = []
        arg = []
        i = 0
        for word in words[2:]:
            if word == '(':
                i += 1
                arg.append(word)
            elif word == ')':
                i -= 1
                arg.append(word)
                if i == 0:
                    args.append(arg)
                    arg = []
            elif i == 0:
                arg.append(word)
                args.append(arg)
                arg = []
            else:
                arg.append(word)
        return args
    
    def expr(words):
        args = getArgs(words)
        args_ = []
        for arg in args:
            if len(arg) == 1:
                args_.append(arg)
            else:
                args_.append(expr(arg))
        
        if lex(words[1]) == "operator":
            return func(words[1])(list(map(lambda a: (type(a) in (list, tuple) and a[0]) or a, args_)))

    lines = code.split("\n")
    for line in lines:
        word = ''
        words = []
        chars = tuple(line)
        
        for i in tuple(line):
            
            if i in ('(', ')'):
                if word: words.append((word, lex(word)))
                words.append((i, lex(i)))
                word = ''
            
            elif i == ' ':
                if word: words.append((word, lex(word)))
                word = ''
                
            else:
                word += i
                
        if word: words.append((word, lex(word)))
    words_ = list(map(lambda arr: arr[0], words))
    return(expr(words_))
Arrays
Data Types
Map/Reduce
Algorithms
Logic

For loops are commonly overused when other Javascript methods can lead to a cleaner and faster solution. A common example would be finding duplicates in an array.

This function called duplicates takes an array of numbers and returns a new array with the numbers duplicated in the original array ordered by value.

Your goal is to refactor this code to still find duplicates in an array and return those duplicates in a new array, but no longer use a for loop.

Note: numbers and their corresponding string representations should not be treated as duplicates (i.e., '1' !== 1).

Based on http://www.codewars.com/kata/find-duplicates/javascript

function duplicates(arr) {
  var out = [];  
  for(var x=0;x<arr.length-1;x++)
  {
    var ch = arr[x];
    for(var y=x+1;y<arr.length;y++)
    {
      var comp = arr[y];
      if (comp === ch && out.indexOf(comp) === -1)
      {
        out.push(comp);
        break;
      }
    }
  }
  out.sort();
  return out;
}