Don't forget to specify the constructor when changing the prototype.
Anyway, best solution for me because left the fullname property out of the constructor ;)

NamedOne.prototype = {
constructor:NamedOne,
(...)
}

When doing:

var addTwo = add(2);
console.log(addTwo == 2) //true
console.log(addTwo(3) == 5) //true
console.log(addTwo(3)(5).valueOf()) //13

The last line should return 10 instead of 13

Try same( [[1,5], [2,7]] , [[0,6], [2,7]] ) and you will see it's not a valid solution.