thanks for showing the correct way to use .sort() for this problem!

unfortunately .sort() will not work properly because it will sort 10 ahead of 2.

will it work then if we add a function to sort? to be sorted numericaly?!

sides.sort((a,b)=> a>b ? 1: -1);

Actually math.sqrt(num) (+1 as range() doesn't returns the upper limit)

I like this pop/push combo here, I used index jumping in my for loop to get this jump over 2 elements :)