Hi,
Because next bigger int for (1234567890) inserted is (1234567908), but not (1234567980) =)
You need to re-check your algorithm or code

my bad I misread

IPs should be considered valid if they consist of four octets, with values between 0 and 255, inclusive.

Why would it be valid?

Why is '12.34.56' not a valid ip?

Could someone explain this please?

Yea I just realized, was just gonna delete it.

are you sure you're not comparing your output with the expected output?

Why is the case "(()))())())()(" not "))))))))))))))"? All the characters appear more than once.

Alright thanks! I see what you mean. My bad for not properly checking.

hi,

Considering the number of completinos in JS, there are close to no chances that the tests are incorrect. Keep in mind you didn't provide the input, so there is nothing to tell, right now. What if the input was 1234567890? Then your code is giving the wrong answer, that's all.

I think there is an issue with random test cases. The value wanted is less than the original value.

Here are some examples of what I am talking about

1234567980 should equal 1234567908
59884848495853 should equal 59884848483559
75530899033 should equal 75530893039

Please correct me if am wrong.

Thanks have a great day

yes sorry I realized after I posted the question.

and it won't be one of the other given digits in the expression.

Asked and answered many times before.