ok

This is sphagetti, please explain the essence of the algorithm if you want help.
(With spoiler flag ofcourse).

??

ohh thanks it worked...i thought it was "a" through "z"...

Modified.

The description says:
"... which given a string will output the error rate of the printer as a string ..."

The problem is to return the error rate, not to output it. I think "output" should be "return" in the above sentence.

This has caused confusion for at least one person working on the problem (Clonewarrior).

Actually both of you are correct - the problem description is wrong:
"which given a string will output the error rate of the printer as a string"

I simply assumed the problem meant returning the string, but the description says "output".

Try typing this into a Python interpreter:
('a' or 'b' or 'c')

Hopefully the result isn't what you expect. I think your "if" statement is the problem.

Same problem happens with C++

printing did not work...it says expected:(true) but was:(false)

That won't be of much help with arrays, try google with "printing an array in java"

System.out.println(input);

so how do i print the input??