Please do not update the solution snippet unless it needs changing.

This is really impressive.
I would love if some one explain it to me.

Incredible)

Wow! Astonished...

Thanks =) i solved it, cool kata!

E.g. in Python:

def count_digit(number, digit, base=10, from_base=10):
  ...
  
count("133", "3")  # is the same as count("133", "3", 10, 10)

# so you don't need to convert the number
#                                vv
# and the digit 3 is 2 times in 133
# therefore the result is 2

Regards,

suic

countDigits("133", "3") == 2 ?? How it works? Maybe .. == 3 ? Give me peace of advice in this question, please.

Good kata. It was interesting, but test cases is very uncomfortable. In the first time, i turned off them that to see my console.log()

Interesting kata. It's helped me to recall work with string compare

Interesting, but too easy like for 5 kuy, I think. And needed random tests.

Great solution! So shorty and cleany, cool!