spoiler flag, guys...

Thanks, I see it. Your answer also is a good reference

its kinda like doing maths how you were taught to do it at school by looping through each digit

can't understand it? can you explain it??

I can't understand it🤔

It is not O(n^2). He's using the same counter to grab the range. It is just O(n).

If mx = 2, then gap(3, 5, 6) return [2, 5], but 2 isn't between 5 and 6.
I believe that the correct way is to write 'mx && m - mx === g'

if gap(2,2,6)
it will be wrong,beacuse you let mx=0 & 2-0=2,so it equals [0,2]

so maybe you can let mx = 2(the lowest prime)

Time complex O(n^2),I think it unnecessary!

best thing ever

真的是太优秀啦