Excuse me! I want to delete the first my comment (but there is no such possibility on the site). I could not determine the algorithm for determining the secret word. And it was not possible for me to learn this algorithm. My opinion is that it would be easier if there were two tests in the task definition, simple and difficult (or medium).

Why not? How do you think this kata has been solved more than 17k times and nobody complained about that test?

As a simplification, you may assume that no letter occurs more than once in the secret string.

"mathisfun" has no repeated letters.

You can assume nothing about the triplets given to you other than that they are valid triplets and that they contain sufficient information to deduce the original string. In particular, this means that the secret string will never contain letters that do not occur in one of the triplets given to you.

With the input given you can recover "mathisfun". Seriously, I don't know what you meant there.

the test for 'whatisup' and the description of the problem condition are absolutely not suitable for the secret 'mathisfun'!!!

There is no such test, and mind your language.

Please read the description again, ['c','b','a'] is not a valid triplet for the string "abc":

A triplet here is defined as a sequence of three letters such that each letter occurs somewhere before the next in the given string. "whi" is a triplet for the string "whatisup".

try:
secret441 = "abc"
triplets441 = [
['c','b','a'],
['a','b','c']
]

Absolute dislike for such a task!!! WRITE IN THE TASK CONDITION ALLOWED RANGE n!!!

This is the wrong solution! Need a 'column addition algorithm'! example: (https://www.mathsisfun.com/numbers/addition-column.html)

There were other definitions of functions in the task condition... example: 'function zero()' not 'const zero'. Not Fair!

I haven't forgotten about js 'eval()' - so I have a little different solution :)