32! in decimal is 263130836933693530167218012160000000

263130836933693530167218012160000000 in base-12 is 7845B61618B173A978800000000000000

which are 14 zeros

Is 14 the correct number of zeros for 32! in base 12? Shouldn't it be 13?

I run into a problem if the last move in the list is the winning move.

For theese moves:
(
[0] => C_Red
[1] => F_Yellow
[2] => G_Red
[3] => B_Yellow
[4] => F_Red
[5] => B_Yellow
[6] => D_Red
[7] => E_Yellow
[8] => G_Red
[9] => D_Yellow
[10] => D_Red
[11] => D_Yellow
[12] => C_Red
[13] => C_Yellow
[14] => D_Red
[15] => C_Yellow
[16] => B_Red
[17] => B_Yellow
)

Yellow is winning on the diagonal from B3 to E0.

But the test expects "Draw" not "Yellow".