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DeniseMDBvs.gaston-areco-tq

Find maximum number that can be formed using digits of a given number

Code
Diff
  • import java.util.Arrays;
import java.util.Collections;

public class MaxNumber {
    public static long print(long number) {
      
      String numberString = Long.toString(number);
      
      Character [] digitos = new Character[numberString.length()];
      
      for(int i = 0; i < numberString.length(); i++){
        digitos[i] = numberString.charAt(i);
      }
      
      Arrays.sort(digitos, Collections.reverseOrder());
       
      StringBuilder maxNumStr = new StringBuilder();
      for (Character digit : digitos){
        maxNumStr.append(digit);
      }
      return Long.parseLong(maxNumStr.toString());
    }
}
    • import java.util.Arrays;
    • import java.util.Collections;
    • public class MaxNumber {
    • public static long print(long number) {
    • return number
    • String numberString = Long.toString(number);
    • Character [] digitos = new Character[numberString.length()];
    • for(int i = 0; i < numberString.length(); i++){
    • digitos[i] = numberString.charAt(i);
    • }
    • Arrays.sort(digitos, Collections.reverseOrder());
    • StringBuilder maxNumStr = new StringBuilder();
    • for (Character digit : digitos){
    • maxNumStr.append(digit);
    • }
    • return Long.parseLong(maxNumStr.toString());
    • }
    • }