thank you for your attention, wow, i don't use python2

this is python 2 code. n/2 -> n//2

This is very clever. I already guessed I didn't have the best solution but I feel very primitive now :D

nice use of abs

nice, walrus is great

You could have written
''.join(' ' * ( abs(n // 2 - i)) + '*' * (n - 2 * abs(n // 2 - i)) + '\n' for i in range(n)) if n > 0 and n % 2 else None

why have you chose variable t:= ?

sure, welcome to constant learning forever and ever and on

Ok, thanks for explanation. I started to code only few weeks ago. :)

this was written in Python 2, where the / behaves as floor div when both values are integers, so replace it with // for this code to work in python 3

Can you really multiply str by float? If I try this code, error occurs.

Please look at my solution.

the abs idea is brilliant!