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SCARED.
Flexing his shredded abs on us! Cool solution!
El resultado está claro, pero... faltaría por declarar la librería a la que corresponde la función"abs()", es decir: #include <math.h>.
I think that the result/return is understandable, but... you have not declared the library for the use of the "abs()" function, I mean: #include <math.h>.
Thanks a lot for your solution!
It's fancy, but it will make a function call and therefore be slower than other functions.
Very smart!
understood the mistake
of the julian calendar year % 100 != 0 - superfluous
really don't understand why...
Hello my code passes tests with years > 1752
and where < 1752 are lost for several days (1, 3 ... somewhere around 10)
in tests, the rule of the julian calendar?
(year % 4 == 0) and (year % 100 != 0) ?
Or am I misunderstanding something, please tell me
i would like at some time in The Future whith god help to be able to come with this kind of simple solutions
there was no year
0
in either the Gregorian and the Julian calendar. the years go from-1 BC
(before Christ) to+1 AD
(anno Domini). I would suggest removing the mention of year0
in the description, and updating the random tests accordinglyfixed
C random tests can generate dates from September 3 - September 13 1752
that should be an issue, i checked the RNG in C and it can indeed generate such dates. raising
no, this is the point, there was no divisible-by-100 exception in the Julian calendar
Ah maybe I get it, you check if l - w != 0, and then add those numbers and multiply them by bitshifting them once. otherwise you're returning the square. Cool solution!
Can you perhaps explain your answer?
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