math...

a little different but in the meantime it's easy to resolve

tbh i dont know abt this

This is a good one for testing performance but not too harshly

Approved

Oh, yeah, I thought 1 digit could only move 1 place, makes sense, my mind went completly blank. Thank you

how is the 0 bigger than 8

That's exactly why your answer isn't correct. There are smaller numbers that are bigger than initial number. 1234567890 < 1234567908 < 1234567980.

Maybe you misunderstood the task, but the clue is in the title.

I think tests are broken on golang, I pass all the random tests, but I fail 2 predetermined ones:

Testing for 1234567890
Expected
    <int>: 1234567980
to equal
    <int>: 1234567908

And

Testing for 59884848459853
Expected
    <int>: 59884848495853
to equal
    <int>: 59884848483559

I am maybe stupid, but that does not seem to be right answers at all, how is the 0 bigger than 8 and then in the second one 9 has to jump to the end?

Nice one, I struggled a bit because I did not read correctly 🤙

For those who are losing their mind on this. It does not requires particular coding skills. Once you get the math (that is not exaclty trivial...) solving it is just few lines of code. If you do not enjoy learning new math you will probably not enjoy this.
Have fun my friends!

My solution))

so that's why I found it easy to understand and still saw people say its "poorly phrased"

Haskell fork adding a fixed test case that should time out for brute-force solutions.