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    This comment is hidden because it contains spoiler information about the solution

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    Hi! I found that new Array(3) is not produce [undefined, undefined, undefined]. It produced [ <3 empty items> ]. And we are cannot to interact with it by Array.prototype methods. We must to convert it to array with Array.from for example.

    > new Array(10)
    [ <10 empty items> ]
    > Array.from(new Array(10))
    [ undefined,
      undefined,
      undefined,
      undefined,
      undefined,
      undefined,
      undefined,
      undefined,
      undefined,
      undefined ]
    
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    You can create arrays like that: new Array(n), where n is quantity of elements. For example, new Array(3) will produce [undefined, undefined, undefined]. Besides, every array has join method, which creates a string from the array's elements and join's argument will play as separator, so that [1,2,3].join('anyStringYouLike') will be evaluated in '1anyStringYouLike2anyStringYouLike3'. And [undefined, undefined, undefined].join('String') will be evaluated in 'StringString'.

    Hope this explanation will help to undestand this solution.

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    I believe Array is a class, and when passed a number like this, it returns an empty array of size n + 1 (empty meaning, each element is undefined).

    Example:

    a = Array(3)
    [ , , ]
    a.length
    3
    a[0]
    undefined
    a.join('hi')
    'hihi'