same but i am using python, have you overcome the timeout issue yet? I am looking for other ways to to solve this kata, instead of using double for loop but am stuck. Any hints are much appreciated.

The parameter your_type && opponent_type is given, so it is guaranteed that there will always be an opponent unless stated otherwise. And when the description did not say to round, then don't round. ~~

Yes it is. Note here it is 3.6 not 3.8 if that makes any difference. Take a look at this

my python code workes on IDE but does not work here, is Python 3 enabled?

if there is no opponent and what should be done should be stated in the description

What do you mean by "no opponent"?

Elixir translation awaiting approval.