I have the same. i got the correct result but it says it is wrong

I have the same question:

	std::cout << firstNSmallest(vector<int>{2, -10, -9, 10, 2, 2, -4, 0, 8, -4, 10, 8, -10, 3, 5, 10, -2, -7, 7, -7, -7, -2, 6, 2, 0, -2, 1, -7, -4, 10, 0, -2, 0, -2, 6, -8, -8, 7, 4}, 38);
	// my answer:
	//[ 2, -10, -9, 10, 2, 2, -4, 0, 8, -4, 10, 8, -10, 3, 5,     -2, -7, 7, -7, -7, -2, 6, 2, 0, -2, 1, -7, -4, 10, 0, -2, 0, -2, 6, -8, -8, 7, 4 ]
	//got
	//[ 2, -10, -9, 10, 2, 2, -4, 0, 8, -4, 	8, -10, 3, 5, 10, -2, -7, 7, -7, -7, -2, 6, 2, 0, -2, 1, -7, -4, 10, 0, -2, 0, -2, 6, -8, -8, 7, 4 ]
	//Expected:
	//[ 2, -10, -9, 10, 2, 2, -4, 0, 8, -4, 10, 8, -10, 3, 5, 10, -2, -7, 7, -7, -7, -2, 6, 2, 0, -2, 1, -7, -4,     0, -2, 0, -2, 6, -8, -8, 7, 4 ]
	std::cout << firstNSmallest(vector<int>{1, 4, -6, -9, -6, -9, -8, 2, -2, -8, -8, -9, -10, 8, 10, -6, 3, 10, 4, 2, 6}, 8);
	//Expected:
	//	[-6, -9, -9, -8, -8, -8, -9, -10]
	//got
	//	[-9, -9, -8, -8, -8, -9, -10, -6]
	//my answer
	//	[-6, -9, -9, -8, -8, -8, -9, -10]

can anyone help?

Sorry, I should read the problem description more carefully。=_=||

what's the difference?

What do you think is the difference between a recursive function with a correct base case, and an incorrect base case?

any tip please..

The default-constructed std::istream_iterator is known as the end-of-stream iterator. When a valid std::istream_iterator reaches the end of the underlying stream, it becomes equal to the end-of-stream iterator.
do you mean that?
thanks for reply.

https://en.cppreference.com/w/cpp/iterator/istream_iterator
http://www.cplusplus.com/reference/iterator/istream_iterator/

Can you explain the parameter "std::istream_iterator()
"What does it mean, I can't find a suitable description in cppref

Expected '#("Robin" "Singh"), but instead got '("Robin" "Singh")
what # mean? I has forget about racket,can someone help?
how can I return a form like '#("Robin" "Singh")?