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Code
Diff
  • fruits = {"Apple": "Red", "Raspberry": "Red", "Strawberry": "Red", "Orange": "Orange","Banana": "Yellow", "Lemon": "Yellow", "Pineapple": "Yellow", "Avocado": "Green", "Lime": "Green", "Melon": "Green", "Pear": "Green", "Blueberry": "Blue", "Huckleberry": "Blue", "Plum": "Purple", "Grape": "Purple", "Maquiberry": "Purple"}
    colour_of_fruit = lambda fruit : fruits[fruit] if fruit in fruits else "Not a fruit!"
    ''' 
        almost oneliner... I am hungry. I'll have a fruit.
        Thanks for creating the dictionary (map) by the way.
        Instead of defining the map fruits, I could just copy
        that map and put it wherever I used it and then, after 
        deleting the comments, it would be a perfect oneliner XD.
        I will leave this chance for someone else XD.
    '''
    • fruit_colours = {
    • "Red": ("Apple", "Raspberry", "Strawberry"),
    • "Orange": ("Orange",),
    • "Yellow": ("Banana", "Lemon", "Pineapple"),
    • "Green": ("Avocado", "Lime", "Melon", "Pear"),
    • "Blue": ("Blueberry", "Huckleberry"),
    • "Purple": ("Plum", "Grape", "Maquiberry")
    • }
    • fruits = {
    • f: c
    • for c, fs in fruit_colours.items()
    • for f in fs
    • }
    • def colour_of_fruit(fruit: str) -> str:
    • """Returns the color of given fruit."""
    • return fruits.get(fruit, "Not a fruit!")
    • fruits = {"Apple": "Red", "Raspberry": "Red", "Strawberry": "Red", "Orange": "Orange","Banana": "Yellow", "Lemon": "Yellow", "Pineapple": "Yellow", "Avocado": "Green", "Lime": "Green", "Melon": "Green", "Pear": "Green", "Blueberry": "Blue", "Huckleberry": "Blue", "Plum": "Purple", "Grape": "Purple", "Maquiberry": "Purple"}
    • colour_of_fruit = lambda fruit : fruits[fruit] if fruit in fruits else "Not a fruit!"
    • '''
    • almost oneliner... I am hungry. I'll have a fruit.
    • Thanks for creating the dictionary (map) by the way.
    • Instead of defining the map fruits, I could just copy
    • that map and put it wherever I used it and then, after
    • deleting the comments, it would be a perfect oneliner XD.
    • I will leave this chance for someone else XD.
    • '''
Code
Diff
  • theletterh = lambda howmuchh : "H" * howmuchh
    • def theletterh(howmuchh=1):
    • for row in range(7):
    • for col in range(5):
    • if col in [0, 4] or (row in [3] and col in [1, 2, 3]):
    • print('H', end='')
    • else:
    • print(end=' ')
    • print()
    • print()
    • return 'H' * howmuchh
    • #H return and H print (H😀😃😁)
    • theletterh = lambda howmuchh : "H" * howmuchh