Yes, sir. Thank you !

can you publish now?

I've added random tests but now I cannot publish the kata.

unpublish your kata meanwhile, or it will probably get retired

Yeah, thank you, will add tomorrow.

You should add random tests

Quite short, nice :)

I made this a long time ago. But if I remember correctly, the distance from from cell 1 to cell 2 must always be computed not by abs(x2-x1) + abs(y2-y2) but instead more precisely with pythagorean's theorem sqrt((x2-x1)^2 + (y2-y1)^2)

Using this formula, the distance of the three spaces in your example from the target or start would be 2, ≈1.41, and 2.

So if i remember the kata correctly, the correct answer is the middle one of those three or (1,1) because it is the closest box within the circle of radius = 2 to the target box (2,2)

I don't understand. Take a look at the following setting :

\begin{matrix}
\circ & \circ & \times & \circ & B \\
\circ & \circ & \circ & \times & \circ \\
\circ & \circ & A & \circ & \times \\
\circ & \circ & \circ & \circ & \circ \\
\circ & \circ & \circ & \circ & \circ
\end{matrix}

where $A$ is where you start from and $B$ is the target cell. The cells with the cross $\times$ inside are all equally distant from the target. This means the kata is not consistent as it assumes that there can be only 2 equidistant cells. Am I missing something ?

Done ! :)

PRESS

How ? I don't have the Republish button anymore --- only Publish ? Should I press it ?

A reminder: Do not forget to republish this kata.

Everything works now. Don't forget to republish the kata.

By the way, there is another way to solve the problem with local variables:

describe('Random tests', function()
  for _ = 1, 20 do
    local n_0, T = math.random(0, 10000), math.random(4, 100) 
    it(string.format("n_0 = %d, T = %d", n_0, T), function()
      assert.are.same({ref(n_0, T)}, {s.pile_size(n_0, T)})
    end)  
  end
end)

Local variables are declared inside the for block and they are different for each loop iteration.