I was so frustrated trying to figure this out. Gave in and tested the top rated solution only to get this. Way she goes.

dud i'm not gona waste 15 minute to learn some stuf not gonna add any knolage to me to just solve one single keta!!!

I made the same mistake. It is:

"true if the sum of the squares of each element in a is strictly greater than the sum of the cubes in b." So cubes for "b" not squares.

I say so!
Stupid condition, nothing is clear from it (((

Format Specification Mini-Language

Then they learn how football scores work from solving this Kata. Thats a win!

Please post as question.

DigitSum(a) is sum of digits of the number (a).

In the example given, solve(29), there are many ways to get 29. One is 15+14. Another is 16 +13, and many other possibilities. The possibility that has the maximum sum of digits is 15+14.

And again, you can't reorder the numbers:

You cannot swap the operands. For instance, in the given example you cannot get expression (1 + 3) * 2 = 8.

Lex88, you don't have to use both operands, you can use + twice.

Please show us what bigger number you can create out of 1, 1, 1 using only the given operators +, *, (), and also show us how. Thanks