WHAT

Iclude "aaaabb" string in test.

all characters in the string appear the same amount of times (3 times), so it returns True

"abcabcd" is NOT a valid word because "a" appears twice, "b" appears twice, "c" appears twice, but "d" only appears once!

got the random test with string "p1imv$!nytsvdfrid%3mxgz!h#!pp11imv$$nnyyttssdffrr%%33xxggzzhh##". so there are letters which can appear twice and once, my code says FALSE, but you want it be TRUE. WHY?

Not a kata issue.

Added another example in the description to make it clearer.

count the number of 1s in the array.

Why are you counting 15s or 10s instead? All the info you need is there, read the description again. I've added a second example to make it clearer.

[15,1,15,1,-3,1,-8,1,-9,1,8,1,10,1,-7,1,-4,1,-5,1]
'15' appears 2 times. so '2' appears 0 times. but this kata says it should be equal 1. why?!
[-10,1,-1,1,7,1,10,1,-2,1,4,1,-3,1,-2,1,2,1,-7,1,11,1,4,1,-3,1,12,1,12,1,-2,1]
'-10'appears 1 time. so '1' appears 16 times. but this kata says it should be equal 0 ...
i think this kata is broken or author should give us much more info

im an idiot. I indexed the wrong thing.

Sorry Chrono79!

character ASCII code, not alphabet position. p is 112.

are you sure?
b=2
d=4
f=6
h=8
j=10
l=12
n=14
p=16

or does the indexing change after c?

You must add up the character ASCII code of each even indexed (assume a 0 based indexing) character in the string

p is not 16.

Another one of those unresolvable issues uh?