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    @hey - The count of sqrt calls is over every test, not just a single call. That is why that test is at the end.

    That makes sense to me. You'd completely cut out that sqrt call. I don't understand what's unclear and/or stupid about that.

    I don't know what's going on with that perf test, but Math.sqrt is a notoriously expensive in all environments and languages. That is why this kata is aimed at reducing those calls as much as possible.

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    This comment is hidden because it contains spoiler information about the solution

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    I agree, this is a bit silly. I am only using ONE Math.sqrt() call. I calculate my determinant, then create var root = Math.sqrt(determinant); How is that FIVE calls? I am calling it once in the function.

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    The answer is almost certainly yes, as my solution got away with the stated minimum number of sqrts. Could you paste in your code, and mark it as "spoiler"? Maybe I (or someone else) could figure it out.

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    Do you ever perform two sqrts in a single quadratic call?