you are wrong, the Morse encoding of the comma is --..--, the dot is .-.-.-, check here. The preloaded Map in Java encodes those correctly

Not an issue, a question.

This might help: https://docs.codewars.com/training/troubleshooting

You know that walls are an area not a volume. So when room is not a perfect cube you need to know dimensions of the walls.

The requirement was unintuitive to me at least and isnt clearly explained anywhere in the description.

@KayleighWasTaken yes, they are, but because w or l is zero... well, these two walls form a 2D rectangle, and since there is zero width of it...

Anyways, for the simplicity, one may say it's zero if any of these variables are zero imho

If w or l is zero, there are still two other walls which can be papered. If h is zero then yes, answer should be zero, but otherwise you can still paper the non-zero-sized walls.

Please possible answer just below.

Nah, wallpaper should be glued on the wall, not the surface; also w*h*l == 0 if any of the variables equals to 0. You may then if the product equals to 0 then either w or h or l is 0 too.

use charAt() method

You cannot compare strings in Java with == (or you can but it will not give you the expected result)
https://www.baeldung.com/java-compare-strings

Hi,

Not an issue, a question (the kata isn't broken, it's just about your code that isn't handling that case properly.

Aside of the obvious answer that "your code doen't do the right thing", we cannot tell with so little information. Try reading a bunch in that wall of text, that might help: https://docs.codewars.com/training/troubleshooting

Cheers