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    there's no problems with comparing characters in the strings.

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    Не совсем верное решение.. Если сравнивать в строке будет не правильный вывод. Нужно сравнивать в Int. Не ужели только я заметил, меня вообще возмутило сравнение в str. И как прошло тесты такое решение?

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    Just now learned I can iterate using .join without 'for'. Thanks!

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    If I'm not mistaken, I think it compares the ascii or unicode number for it. '4' in ascii would be int 52 and '5' would be int 53, '6' is int 54 and so forth so anything below int 53, put a '0' and anything above put a '1'

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    intresting it just compiled all the 4-5 lines of code to a one liner (but, i'm being honest here it can be optimised)...
    REGARDLESS, GOOD JOB

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    Great job, I decided as well.

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    Nice dude I spent so much time on this problem

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    strings are ordered lexicographically

    and if you attempt to compare a string to an int then whichever one of them you ask they'll tell you they don't know which comes first. (operators boil down to method calls on one of the operands. you're asking one of the values if it's smaller than the other)

    javascript on the other hand, is a mistake, and will convert mixed values into a single type and then compare for you. all friendly and with a smile on its face. "friendly" here really just means it did something other than what you said, which is a great way to make your code full of difficult to find bugs.

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    hi natan, could you please explain how the code treats this?

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    that is not what happens, for example, '9' is not less than '10'

    languages shouldn't guess what's meant, they should do what is said

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    good to know that you could use c < '5' and it will automatically treat the string value to int, instead of using the int() function on the individual string value.

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    always the oneliners :-:

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    Ahh I see now, was wondering how they could possible use "<" operator when comparing an int with a string. My mistake.

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    The input is not an integer in the first place, it's string. That's why it's iterable.

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