O(n) since it involves finding the element twise, and also approach modifying the array.

Seeing your solution: Simple is not easy. Chapeau!

So there should be an algorithm to take off the solutions that don't pass new tests, no ?
If not, it's misleading to read solutions not working anymore.

Yes they were.

This solution doesnt work because it fails for
negative numbers : 1.2.3.-7

And also for strings with more than 4 groups of number with anything other than numbers as: 1.2.3.4.z

How has this solution passed the kata ?
Maybe the tests were different at the time ?

Ok now i know how stupid i am

but he wouldn't have passed the tests if there had been a flow, right?

If you add some invalid data after dot like '1.2.3.4.asdf' the total amount of valid numbers would be 4 and function will return 'true'

i wonder why you know this trick, i feel there are many weird terms of math linear
great solution

isValidIP('-12.-233.200.128')
true

It's so cool to use 'v==Number(v).toString()'. But to filter out non-numbers and negative numbers is necessary.

How does this solution filters negative numbers?

beautiful. well done!