Your latest solution is wrong because

• You use index to check positioning of the corresponding word to replace, this will fail if the title contains 2 or more identical space-separated words (same casing as well)

• You're checking whether word in title is also part of a sub-word in minor_words instead of individual words there

Your code will compare numbers against itself (which fails for cases when n = 0) since the diff between a number and itself is always 0

Someone already told me 2 years ago but thanks.

There will be a preloaded dictionary dict_scores with all these values: dict_scores["E"] == 1

This is from the instruction.

Dayum.

In this kata, a difference seems to be defined as non-negative integer. So, there are no pairs when a negative n is given. And also, think carefully for n==0 case (e.g. lst=[1,1,1],n=0). When you want to check the input values, try to add a temporary code like "print(lst,n)"

yes, i am also having this issue. i don't know to pass test. because i don't know the problem with my code

oh haha, thanks!

I don't understand why every response he makes is so passive-aggressive. You'd think he hates to responding to people how he acts.

It simply doesn't exist there. You'd need to print dict_scores from the kata, then copy / paste it into your foreign environment.

I'm confused, this isn't working in PyCharm because it doesn't know where the dict_scores variable is coming from.

I was just improving his code without changing it too much.

Please, don't post code in kumite's comments, it can't be marked as having spoiler content and are visible in the home page

`
def getCount(word):
print(len([current_letter for current_letter in word if current_letter.lower() in 'aeiou']))

getCount('Abracadabra')
`

Would run slightly faster as a list comprehension. Also, because strings are indexed by letter, "aeiou" doesn't need separate strings.