cool

Yes. bitwise-or of the modulo(remainder). It is only zero if both modulos are zero.
When using it on bools you have to be a bit careful, as (1 | 2) is 0011, and that is stored in boolean. true is 0001, so while (1 | 2) evalutes to true, it's not equal to true in some way. Here it's fine, but be aware. Negating with ! (boolean not) "normalizes" it to 0000 or 0001 though. ~ would be the bitwise not.

bitwise-or may be faster as it does not branch (both sides are always evaluated), as opposed to boolean or. But don't rely on that.

is this the bitwise OR operator?

nice man good job ?? !!

Approved

python new test framework is required. updated in this fork

the error is still there

Approved

python new test framework is required. updated in this fork

it's really clever but indentation is not very good.

nice coding

You can just print the input: random testing reaches up to n = 100,000

I am running in a timeout when submitting my solution. I tested it for a limit of 1500 without running in a timeout.
Which is the highest number use in the tests?
Thx

there is a difference between a person trying to solve a 7kyu, i guess, it is not at all a 7 kyu at least needs to be 5 kyu. of course for "dan's" it might be a single line, but the complexity level should be set according to a person most likely to solve it i.e. a newbee.