He's right, read the other note:

Don't forget to convert the percent parameter as a percentage in the body of your function: if the parameter percent is 2 you have to convert it to 0.02.

Very naive of you not to read instructions.

"There are no fractions of people. At the end of each year, the population count is an integer: 252.8 people round down to 252 persons."

"Given a number n, return the number of positive odd numbers below n, EASY!"

Here I thought I was being clever... and completely overlooked the simpler solution.

Why do you use long type for the digit?

What would happen if "int n == -15", for example?.. Where is the checking for positive/negative int?

me too!!

why /100 in every iteration of the loop. You can save calculations by /100 outside of loop very naive

oh, I apologize, I'm wrong. I forgot that the number n is not taken into account.

You only need to return the n positive odd numbers that comes before the given n.

for n=1 or n=3? or n=-10? something wrong.