Generate a sequence of 500 numbers using the rules given. Then you will be given index numbers and you will return the number at that index. The number at index 100 is 103.

hello I am having a problem understanding this kata,
This is the problem that I am facing :
In the tests there is this one findNum(100), Equals(103)
according to what I understood the number in the result can't
have the same digits that the input has, 1 and 0 from 100 are exsisted in 103.

Both algorithms are linear on the input; but yes, this one is faster

I think that no number has a divisor larger than it's half other than itself too .