you got me, no joke

it seems like if there's a real large string, it's gonna have to fully convert it to upper case and compare. i guess a for loop with an early return false (in case a char is lowercase) would be the best practice in terms of performance

you told already what i was thinking to say. well done. 👏

alright i'm sorry

Hi Sara,

I would suggest you to try to run the code. The module operator (%) return the reminder in the division between the first and the second number. 6 divided by 2 is 3 with 0 as remainder, so in this code would be select the first item in the tuple, "Even", that is correct. Your version is easier to understand and more suitable for python, but the code written by graf_da still works.

if i enter "6", your code will throw KeyError because 6 % 2 == 2. so i'd rather do

def even_or_odd(n: int) -> str:
  return 'Even' if n % 2 == 0 else 'Odd

that's genius

just for lulz

why did you name the argument $?

agree