this seems very uneficient

Is this not considered kind of cheap though by using hardcoded entries for multi-symbol values like IV, IX, XL, etc.? I thought that the "proper" solution would only use what was shown in the challenge prompt as hardcoded symbol/value pairs.

Idk about my solution compare to this one, probably mine is worst like 80% of the time (I'm starting in js);

@Chrono79 This won't happen in next time. Thank you!

Please, don't forget using spoiler flag next time.

Agreed its not very scalable; yours is much nicer

I did something very similar. I think this is a clever solution in terms of a small LOC but not in terms of performance (i.e. repeatedly breaking the for loop and restarting the iteration back at square one). I did something similiar however I didn't stop the loop when decrementing the number value until it was time to move on to the next roman numeral thus I never had to restart the algorithm. Thanks anyway

This is so clever solution, I just create array 2 arrays and check it.

should not with 900&400&90&40....so i think it not a good answer