when your maxed out player does side quests at the end

Sorry - it must be:

int maxtest = (int) Math.sqrt(num)+1;  
return IntStream.range(2, maxtest).noneMatch(divider -> (num % divider) == 0); 

The endvalue of then IntStrem can be the squareroot of num. If no lower divider is found, there is no at all!

int maxtest = (int) Math.sqrt(num);  
return IntStream.range(2, maxtest).noneMatch(divider -> (num % divider) == 0); 

Thats much faster!

Try to review and optimize your code

My code is correct as I test it on my local computer. But it takes too much time to run here and failed with an execution error. Maybe the problem is with my connection. Any ideas please?

Wow now I got we can do switch statements inside return like this. Nce trick!