in the solution you assume that quantity of whitespace delimited numbers are not more than 27 which is len('+-/+-/+-/+-/+-/+-/+-'), so what if the quantity is more than 27 ?

Nice solution but function find_letter is invoked unnecessarly too much

no need to check if word exists

Very clever

Thanks, very explanatory

You could have written
''.join(' ' * ( abs(n // 2 - i)) + '*' * (n - 2 * abs(n // 2 - i)) + '\n' for i in range(n)) if n > 0 and n % 2 else None

why have you chose variable t:= ?

:)))))