Mind the input validation.

except TypeError, lol :D

>>> 16.0 == 4 ** 2
True

very childish +rep

Should not have been translated.

The rank is appropriate for some kata languages. If anything, languages for which this rank is not appropriate should have their translation taken off the kata, not the kata rank changed.

It simply changes the tuple args into a string literal, meaning it contains all spaces and punctuation as well as brackets.
I'm not a fan of this solution though, it iterates through that whole (in worst case) literal ten times.

yes

So in this case the delimiter '\n\ will be applied after each loop, right?

definitively !!!

Holy moly, what i've done, it was so simple

I think that n%3 mean that a number divide by 3 and what you want is the remainder. n//3%3 mean that you are diving the number dirst and rounding it down, then you are doinging another division and looking for it's remainder. Same with n//9%3 This just mean that you are dividing by 9 first and rounding down, then you divide by 3 and get the remainder.
For example;
5%3 would have a remainder of 2.
5//3%3 would be 1.66 and round down would have 1, then you find the remainder which is 1.
12//9%3 would be 1.33 and round down you get 1, then you find the remainder of 1/3 which is 1.

I mean how you are calculating the exact hands by dividing. I could think of three nested(one for each person ) for loops that gives me array of numbers, but I was failing to stop the 3 nested at exact hands given as input