You used my previous solution ;)

#you can use this code for less confusion
is_even = lambda a: a%2==0

The left side of the comparison determines if the variable is NOT an "existing"true or an "integer""not a decimal", the result is undefined

If the left of the comparison fails, then we move to the right comparison

If the integer is odd then return false, else return true.

0 is False and 1 is True

do you want it to return 0 when not even, and 1 when even?

Because this is kumite. Here it's about showing off skills related to the knowledge of tricks to reduce the length of the code as much as possible, I think. Of course, in "normal" code readability is very important.

Why you dont return simple undefined instead od {}.a ?

I mean:
isEven=n=> n%1==0 ? !(n%2) : undefined

and this is more readability. When you put some whitespace beetween

0

Well done! I didn't know the trick {}.a for undefined...

*chef's kiss* now with 100% less ord()!

great minds! I edited the previous fork + added some regex to strip leading spaces and comments

The more you know about obscure inline ASM hacks... :D

Thank you! :D

nice one

Still, mine is shorter mwehehe