thank you good sir!

it is enough to add a break statement under the if statement

I feel like the solution to creating a min or max function shouldn't rely on using the actual min or max function, so your solution gets my vote for best practice.

this would break if there are multiple consecutive spaces

Wow, is a genius

Python doesn't have arrays and the code above isn't creating a list either. It's creating a generator and the creation specifically takes almost no resource, since the values are generated lazily.

AFAIK the difference comes from the code above calling isdigit function a lot of times, whereas replace is only called 10 times. Keep in mind, that both of the functions are highly optimized and written in C, so that's why the the code with more function calls and more python is slower. That also for example causes some O(n^2) algorithms to run faster in python, than an O(n log n) alternative.

xor solution is n. Most efficient

Good one! You also are good writing without "!=0" because boolean for "0" would be "False" anyway, and all others would be "True!
I used set, but actually this one is shorter, maybe it's more expensive if talking about productivity...
Thank you!

great solution

This is so effective, instead of double looping to create 2 lists...

Mutating an argument is the worst thing you can do.

I really like this solution ngl, clever!

This solution is awesome, I feel like a simple amateur. Congrats!