Not sure you can do much different than that...

what they want is the position in the array not the value.

ex:

numbers = "2 4 5 6"

In this case the number 5 is the odd number and it is in the third(3) position.

return true if the walk the app gives you will take you exactly ten minutes

The test is ok. Please read this: https://github.com/codewars/codewars.com/wiki/Troubleshooting-your-solution

hi the second test on the java version has a mistake, it should return true.
proof:

assertEquals("Should return false", false, TenMinWalk.isValid(new char[] {'w','e','w','e','w','e','w','e','w','e','w','e'}));