i did this

since his sum is already declared 0, it will return 0 if list is empty.

Since sum is declared as 0, in case of an empty list it returns 0. Or am i mistaken?

This is what I think the author was looking for, though you might be missing the part about returning 0 if the list is empty.

In the final test I am getting 1 as the midpoint sum and I dont really understand how that isn't the correct answer. [1, (1), 1, ...] 1 == 1 when comparing from the index (1) within the parenthesis.

def midpoint_sum(ints):
if len(ints) <= 2:
return None
for i in range(len(ints)):
left = sum(range(ints[i-1]))
right = sum(range(ints[i+1,len(ints)]))
if sum(left)==sum(right):
return i
return None

Hey peeps.
I am getting an error because it is encountering tuples, any clue why?