I got confused at the end here.
return xs.length ? xs.join(", ") + " & " + x : x || ""
I know in ES6, after ":" it is equal to "else return"; But I got confused with the "||". I know it meant "or" but how does the function knows that which option to choose between x or "" ?
So confused.
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wow
Jeenyus
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actual genius here
Love the brevity but it takes some time to understand.
pop() is a good use here.
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Considering all possibilities, a good logic!
You are looping over the names twice. It is possible to solve this with better time complexity.
Nice and short solution though.
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I got confused at the end here.
return xs.length ? xs.join(", ") + " & " + x : x || ""
I know in ES6, after ":" it is equal to "else return"; But I got confused with the "||". I know it meant "or" but how does the function knows that which option to choose between x or "" ?
So confused.
[1].pop() will return 1, not undefined.