Hi @Kippe and welcome to Codewars!

You are allowed to pick a contiguous subarray of any length not just length = 4.

So in the array you are asking about it turns out that the answer is the entire array sums up to 155 which is the maximum possible.

Meanwhile, in the array [-1,-1,-2,100,230,-5,-7] the answer would be the subarray [100,230] which produces a sum of 330 which is the maximum possible, as for example including [-2,100,230,-5] would be less than 330 etc.

Hi,

i thought i understand, but how can
([7, 4, 11, -11, 39, 36, 10, -6, 37, -10, -32, 44, -26, -34, 43, 43]), 155)
sum up to 155? I dont see a substring of length 4 in this that could return 155.

Hi @Y0z64 and welcome to Codewars! Congratulations on solving, but please don't post spoilers to kata in the Discourse - the goal is for people to solve on their own.

If you do want to discuss specific implementations you should use the Spoiler flag; this makes your comment invisible to people who have not yet solved the kata.

No .format() solution because im way to lazy to understand how that works.
Still, this works

Please use spoiler flag next time.

I made a whole function to separate the number from each word and added it to the same list to make a 2d table, afther that i used list comprehension to sort the words and at the same time eliminate the number, all of this last part inside a " ".join(...) to transform the array again into a string.

The problem is that I realized way to late that by sorting again each word the number is separated and put in the first position of the array (so word[0]) so the whole function to separate the number is unnecesary. Plus this can be done inside the sorted() by using "key = lambda x:sorted(x)" efectivly sorting two times in a row and automatically sorting each word into place.

Even though big part of my code is unnecessary im proud i could solve this problem by myself and without the use of external libraries.

I just realized you dont need to turn it into an array becuase you can use sorted() on strings so just do sorted(srt(num),reverse=True
Also there is no need to create a variable to return and can just write the "".join(...) directly into the return