Nah, I've seen the one with stupid algorithm which can be solved by hardcoding.

How the hell is this possible?? I have 3 characters to work with

Wait.. the function you're in is called Remove, and you're calling it inside itself. Which isn't necessarily always an issue, but there's only 1 argument to Remove(string s) and you're passing 2 when you call it in the line string result = s.Remove(i, 1)

The range of difficulty of 8kyu problems is very wide. That being said I liked this problem. 8kyu though? Hmm...

Worst one on this site that I've come across. good lord

i+1 on the last loop iteration is greater than the length of the string and thus is undefined.

Very grateful for the 2xp this epic kata gave me

Because test cases use round(your_result), and None isn't valid argument for it. Just return 0 or something...

i just write "Pass", to see some test cases , but it still showing error

Thanks alot. Your explanation did make a bit more sense than that obscure manual :-)

Easiest 7kyu? All it takes is knowing the formula.

also Python:
[1.5, 2.5, 4, 2, 1, 1]
1.0833 should be close to 1.0833333333333333 with absolute or relative margin of 1e-09

Too restricted delta check? Only if I don't round upto 4 decimals, I pass the Kata.

It's a very old kata (7 years old). Back then ranks were inflated.

Easiest 5kyu ever.
This must be a mistake, right?

Had the biggest brainfart with this one because I was dividing by the mean in the end instead of the # of elements... woops