The $ is just a character in the string. Is there a reason you think it would need to be escaped?

How come the $ does not need to be escaped in this solution?

I agree with waldnzwrld. that is not the porpus of this kata.

I'd .round(2) just once, wrapping all the return sentence. Otherwise, I liked it!

the ^ is a logical xor not a bitwise xor

this is the best

Thanks

This is the so called "ternary operator":
http://www.w3resource.com/ruby/ruby-ternary-operator.php

condition ? something : something-else

is a shortcut for:

if condition
  something
else
  something-else
end

what does ? and : mean in ruby

Hehe, sorry, I thought perfect square would be enough. It's fixed now.

The instructions should be more explicit about the number being passed in, and the condition that it must result in a whole number when the square root is calculated.