Tests updated.

Also, it should be rewritten to be more consistent with numbers versus integers.

I saw some of the "correct anwsers" and they should not be accepted.
Please, someone write this test:

  Test.assertEquals(cubeOdd(["12","9"]), undefined);

Edit:

This chanllenge needs to be rewriten if you really want to return undefined if any of the values aren't numbers.

That was a little tricky one. I had to scratch my head for a while to find a solution. I'll made a suggestion for the newcomers read the intsructions carefully.

This depends a lot on the definition of "power of two" you establish. We could be allowing rational exponents (square roots). Even Integer exponents would start a painful process as 2^(-2) (1/4) would be a valid parameter. With the same rules we could say that exponents are only Natural, then 1 would not be a power of two.

I take your point and very much agree that we should definitely define the Range of exponents we are taking into account.

There's a bug in the test cases and width the biwised solutions. 0 is not a power of two cause any number powered to 0 equals 1, so there should be two mandatory tests:

Test.assertEquals(isPowerOfTwo(0), false);
Test.assertEquals(isPowerOfTwo(1), true);