list.index(num) always return the first index which equal to the num
for example : a = [2,3,3,2] a.index(2) -> 0 a.index(3) -> 1
It should find two different items in the array
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[0, 0]
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list.index(num) always return the first index which equal to the num
for example :
a = [2,3,3,2]
a.index(2) -> 0
a.index(3) -> 1
[0, 0]is not a valid answer. Please mark your post as having spoiler content next time, and read this: https://docs.codewars.com/training/troubleshooting/This comment is hidden because it contains spoiler information about the solution