hi, made changes

Why is name parameter dynamic? Is there anything wrong with making it just String?

Hi, the test is correct. The result should be 2.

[-1, 1, 0, -1, 1, 0, -1, 1, 0, 0] input data
[ 0, 1, 2,  3, 4, 5,  6, 7, 8, 9] data index
[-1,1] == 2 == [-1,1,0,-1,1,0,0] the sum of the numbers on the right and on the left are equal
[] != 0 != [1,0,-1,1,0,-1,1,0,0] on the left sum to zero and on the right sum to 1

thank you

done for Ruby; JS already done

Codewars challenge api
https://www.codewars.com/api/v1/code-challenges/582e0e592029ea10530009ce

Hi, how do I know who approved the kata

fixed it, thanks.

found the problem there are no simple tests

Hi, I'm the author of the translation, what problem are you talking about, please specify.

Hi, thanks for taking the time to look at my problem. I'll make changes later.

Hi, the solution will pass only if you find a way to solve the problem without loops. as wrotes below in the comments inList numbers are sequentially from 1 to n this should help you to solve the problem without loops

your solution has a bug that incorrectly handles four zeros in sequence
example input data [9, 0, 0, 0, 0, 0, 9]
your code will return [ 9, 0, 9, 0, 0, 0, 0, 0 ]

Suggestions:

• Change return type of add to int Function(int) add(int n){ ... } and solution setup to something like:

/* insert return type */ add(int n){
  return;
}

I think that this looks much nicer in strongly typed languages. If someone will solve it with dynamic then fine, but static types are so much neater :)

• Perform two assertions, where first one checks what is returned by add(x). Users who do not know how to do "functions in functions" will attempt to return strange things from add, and tests will crash attempting to call an uncallable thing, resulting in confusing failure messages. You can try something like expect(add(x), isA<int Function(int)>(), reason: "\nadd(x) should return a function");, maybe extracted to a helper function like following pseudocode:

function dotest(a, b, expected) {
  wrapper = add(a);
  expect(wrapper, isFunction<int->int>);
  actual = wrapper(b);
  expect(actual, equal(expectd));
}

(make sure to use reason: for clear failure messages).

Hi I checked
your code gives wrong result for
this sequence [9, 0, 0, 0, 9, 1, 2, 0,
1, 0, 1, 0, 3, 0, 0, 1,
9, 0, 0, 0, 0, 0, 0, 9] can you check locally