fetch! i didn't and I see that it was for lack of ";\nsorted"

the compiler said that it was ()

Yeah. It was unfortunately deprecated. Beautiful solution though

Beware of big numbers, tail-call optimization is not used here! For more information about Elixir tail-call optimization, read the official docs regarding recursion https://elixir-lang.org/getting-started/recursion.html where (at the moment of writing) is a link to the wikipedia "tail-call" page.

The useless

int cmd = std::stoi(packet.substr(4,4));

was the problem, when an invalid base 10 command is received, an exception is thrown.

I won't try, but I'm sure all the solutions I'd tried were rigth

Thank you

Seeya

I've just checked it, and according to this SO question starting from C++ 11 string are immutable objects (as I thougt from the beginning).

Trying using int -> string conversions and string concatenation instead.

I totally agree with your logic, copying your example in its entirity and using the g++ compiler runs and produces the correct result without issue.

This is certainly an issue with how the code is compiled/run in the Kata environment, and not a product of the kata itself.

I will mark this as resolved for now, but please feel free to continue the discussion :)

You can add char and int because char is int (partially).

I'm not sure, but I have an insane theory that after mutating the string like you are doing, something really bad happens to it. Try using working with a string as if it was a string (and not a char array (duh)), and I think it may work then.

Resolved.

Approved, thank you for your contribution!

This is your issue:

out[8] = '0' + result % 10;

You are trying to add together a character and an integer.

Please let me know if your solution works and I will mark this as resolved.

Ps. The way that you are checking for the instruction is clever!

NASM Translation Kumited - please accept :D

Could you share what you have? Mark it with a spoiler flag please thanks!