Ranks can't be changed

Thanks! You too, happy new year also!

Solved but this one should be lower kata because it was difficult not that simple as 7kyu.

Good job keep going.

How long you are learning python?

ty

Probably your solution isn't 100% right and that is catched sometimes with the random tests.

I press once solution is not correct , i press again solution is correct but i didn't change anything why is this happen?

Tests cases are good but description is not good , i want to say you if there's another word the counting will start from zero.
For example:

ThIs Is A TeSt --> every word counting starts at zero not as you think.

similar to your approach good one , but as @kclaw99 says it is not that much efficient because strings are immutuable but the step by step solution is very good.

It seems easy question at beginning , but definetly it was logic one!

Please rewrite the description i am confused.

Solved but this kata is a little bit difficult than 6kuy.

You need to return the top 3...
It's literally the name of the function and it also says so in the first sentence of the description.

print(top_3_words("e e e e DDD ddd DdD: ddd ddd aa aA Aa, bb cc cC e e e")) # ['e', 'ddd', 'aa']
It says return top two words or one if have why it is aa in the output why are not e and dddd?