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I think you need to edit task. There were written: sum of two cubes in two different ways. But in fact the wright solution is: two and more different ways
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Sorry for the misunderstanding, I must've misread the text
Thanks!
dani is correct, you need to be able to express the number as two different sets of two cubes in order to return true.
The description says to check if the number can be written as the sum of two cubes in two different ways, there's nothing to suggest that it can only be written in two ways.
The description of the kata or the tests need to be corrected.
To me, the kata asks to check if a number can be written as the sum of two cubes in EXACTLY two ways. But if we test for EXACTLY two pairs, we fail the tests. The tests consider correct a number that can be written as the sum of two cubes in AT LEAST two ways.
I may be reading the text wrong, but the number has to be written as the sum of cubes in two ways. n=a^3+b^3=c^3+d^3, where a,b,c,d are positive and different.
From what you are saying, for 46163 you've only managed to find a pair of numbers that satisfy that condition
Personally, onet thing I do when I'm not provided enough context with code wars is to try it on my own machine and try to debug it from there. It really helps.
Mednoob, thank you for your reply!
This comment is hidden because it contains spoiler information about the solution
This comment is hidden because it contains spoiler information about the solution