I can't tell what language you are using. At first, I thought it may be JavaScript ( but I see you have a lower case "null". However, if it was JavaScript, when using the .sort() method, the array components are converted to strings. In that case, "1" will be followed by "10". To compare numbers, you need a call back comparison function within the method. Might be some case like this for the language you are using. Besides that error, did the message log out your returned result?

It also depends if a person solves it by scratch and not by using built-in or imported sorting functions or methods.

Awesome thanks!

I tried this in Csh and it failed the test cases, but unless I'm missing something, it passes the example cases in the terminal. Can you confirm that this will work with Csh?

This solution is time O(n), so a best practice solution. Many others, including my first attempt are O(n^2)

I suggest rewording the description for JavaScript from: "Write a class function named repeat()" to "Write a function named repeat()", because even though the problem starts with function repeater(), someone may believe the solution was supposed to start with the class keyword, or take the form of a method under a class constructor.

In JavaScript, .join() is an Array method, not a String method.

["foo", "bar"].join('');    // "foobar"
"foo".join("bar");          // VM910:2 Uncaught TypeError: "foo".join is not a function(…)

To put two strings together, you would use the .concat() method, or use the "+" operator.

"foo".concat("bar");        // "foobar"
"foo" + "bar";              // "foobar"

Just curious, what is the danger in using for...in with arrays?

Ha yeah, actually it was a really good practice exercise for a shell one-liner...

sed "s/^[ \t]*/\'/g" dictionary | sed "s/:/\' :/g"

:)